Gaseous StateHard
Question
500 ml of a hydrocarbon gas burnt in excess of oxygen yields 2500 ml of CO2 and 3 lts of water vapours. All volume being measured at the same temperature and pressure. The formula of the hydrocarbon is
Options
A.C5H10
B.C5H12
C.C4H10
D.C4H8
Solution
CxHy + O2 → CO2 + H2O
x × nCxHy = nCO2 (POAC on C)
x × 500 = 2500 (x = 5)
y × nCx Hy = 2 × nH2O (POAC on H)
y × 500 = 2 × 3000 y = 12
Formula = C5H12
x × nCxHy = nCO2 (POAC on C)
x × 500 = 2500 (x = 5)
y × nCx Hy = 2 × nH2O (POAC on H)
y × 500 = 2 × 3000 y = 12
Formula = C5H12
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