SHMMedium
Question
A block is in equilibrium at rest in a lift as shown in figure. Now lift starts accelerating. The minimum magnitude of acceleration of lift for which block will touch the floor of lift, is
Options
A.
B.
C.
D.
Solution
From work energy theorem Wg + Wpseude + Wspring = ᐃKE
⇒ Mgh + Mah +
kx2 - k (h + x)2 = 0 where Mg = kx
⇒ Mgh + Mah - kh2 - khx = 0 ∴ a = 
⇒ Mgh + Mah +
kx2 - k (h + x)2 = 0 where Mg = kx⇒ Mgh + Mah -
kh2 - khx = 0 ∴ a = Create a free account to view solution
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