SHMHard
Question
A block is in equilibrium at rest in a lift as shown in figure. Now lift starts accelerating. The minimum magnitude of acceleration of lift for which block will touch the floor of lift, is
Options
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Solution
From work energy theorem Wg + Wpseude + Wspring = ᐃKE
⇒ Mgh + Mah +
kx2 - k (h + x)2 = 0 where Mg = kx
⇒ Mgh + Mah - kh2 - khx = 0 ∴ a = 
⇒ Mgh + Mah +
kx2 - k (h + x)2 = 0 where Mg = kx⇒ Mgh + Mah -
kh2 - khx = 0 ∴ a = Create a free account to view solution
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