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Question

A mass m is suspended from a spring of length l and force constant K. The frequency of vibration of mass is f1. The spring is cut into two equal parts and the some mass is suspended from one of the parts. The new frequency of vibration of mass is f2. Which of the following relations between the frequencies is correct :-

Options

A.f1 = √2 f2
B.f1 =  f2
C.f1 =  2f2
D.f2 =  √2f1

Solution

When spring is cut into two equal parts then spring constant of each part will be 2K and
f ∝ √K
New frequency will be √2 times so f2 = √2f1

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