SHMHard
Question
The potential energy of a 1 kg particle free move along the x-axis is given by
V(x) =
J
The total mechanical energy of the particle 2 J. Then, the maximum speed (in m/s) is
V(x) =
J The total mechanical energy of the particle 2 J. Then, the maximum speed (in m/s) is
Options
A.2
B.3/√2
C.√2
D.1/√2
Solution
kEmax = ET - Umin
Umin(±1) = - 1/4J
KEmax = 9/4 J ⇒ U =
J
Umin(±1) = - 1/4J
KEmax = 9/4 J ⇒ U =
JCreate a free account to view solution
View Solution FreeMore SHM Questions
The oscillation of a body on a smooth horizontal surface is represented by the equation, X = Acos(ωt) where X = dis...A pendulum is swinging in an elevator. Its perioed will be greasted when the elevator is...The distance between the point of suspension and the centre of gravity of a compound pendulum is l and the radius of gyr...Time period of a spring mass system can be changed by...The displacement of a particle in S.H.M. is x = a sinωt. Which of the following graph between displacement and time...