Gaseous StateHard
Question
Two glass bulbs A (of 100 mL capacity), and B (of 150 mL capacity) containing same gas are connected by a small tube of negligible volume. At particular temperature the pressure in A was found to be 20 times more than that in bulb B. The stopcock is opened without changing the temperature. The pressure in A will
Options
A.drop by 75%
B.drop by 57%
C.drop by 25%
D.will remain same
Solution
nT = nA + nB
PfVf = PAVA + PBVB
Pf =
Decrease in P of A = 20 P -
P
% drop =
P × 
× 100 = 57%.
PfVf = PAVA + PBVB
Pf =
Decrease in P of A = 20 P -
P% drop =
P × × 100 = 57%.Create a free account to view solution
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