Gaseous StateHard
Question
For two gases, A and B with molecular weights MA and MB, it is observed that at a certain temperature, T, the mean velocity of A is equal to the root mean square velocity of B. Thus the mean velocity of A can be made equal to the mean velocity of B, if
Options
A.A is at temperature, T1 and B at T2 T1 > T2
B.A is lowered to a temperature T2 < T while B is at T
C.Both A and B are raised to a higher temperature
D.Both A and B are lowered in temperature
Solution
Given 
⇒ 8MB = 3π MA
&
⇒ 
⇒ MB . TA = MA . TB
⇒
MA . TA = MA . TB ⇒ TB > TA Hence (B)
⇒ 8MB = 3π MA&
⇒ ⇒ MB . TA = MA . TB ⇒
MA . TA = MA . TB ⇒ TB > TA Hence (B)Create a free account to view solution
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