Gaseous StateHard

Question

For two gases, A and B with molecular weights MA and MB, it is observed that at a certain temperature, T, the mean velocity of A is equal to the root mean square velocity of B. Thus the mean velocity of A can be made equal to the mean velocity of B, if

Options

A.A is at temperature, T1 and B at T2 T1 > T2
B.A is lowered to a temperature T2 < T while B is at T
C.Both A and B are raised to a higher temperature
D.Both A and B are lowered in temperature

Solution

Given      ⇒ 8MB = 3π MA
&     ⇒  ⇒ MB . TA  = MA . TB
⇒ MA . TA = MA . TB       ⇒ TB > TA  Hence (B)

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