Chemical Kinetics and Nuclear ChemistryHard

Question

Consider the following complex ions P, Q and R ,
P = [FeF6]3- , Q = [V(H2O)6]2+ and R = [Fe(H2O)6]2+
The correct order of the complex ions, according to their spin-only magnetic moment values (in B.M.)is -

Options

A.R < Q < P
B.Q < R < P
C.R < P < Q
D.Q < P < R

Solution

spin only magnetic moment
n → number of unpaired electrons
P : [FeF6]3-
F- → (weak field ligand)
0  < P
Fe3+ ; [Ar] 3d5
number of unpaired electron = 5

Q : [V(H2O)6]2+ 
H2O → (weak field ligand)
0  < P
V2+ → [Ar]3d3 
number of unpaired electron = 3

R : [Fe(H2O)6]2+ 
H2O → (weak field ligand)
0  < P
Fe2+ ; [Ar] 3d6 
number of unpaired electron = 4

Hence, Ans (B) : Q < R < P

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