ElectrochemistryHard

Question

100 mL of buffer of 1 M NH3(aq) and 1 M NH4+(aq) are placed in two comparments of a voltaic cell separately. A current of 1.5 A is passed through both cells for 20 min. If only electrolysis of water takes place. then

Options

A.pH of LHE half cell will increase
B.pH of RHE half cell will increase
C.pH of both half cell will increase
D.pH of both half cell will increase

Solution

Cathode (RHE): 2H2O(l) + 2e- → H2(g) + 2OH (aq)
Anode (LHE): 2H2O(l) + 2e-  → O2(g) + 4H+(aq) + 4e-
In RHE, OH+ will be produced which will react with NH4+ (salt) to from NH4OH (base), causing pOH to decrease or pH to increase.
In LHE, H+ will be produced with will react with NH4OH (base) to from NH4+ (salt)  causing pOH to increase or pH to decrease.

Create a free account to view solution

View Solution Free
Topic: Electrochemistry·Practice all Electrochemistry questions

More Electrochemistry Questions