ElectrochemistryHard
Question
Consider the cell
Ag. The measured EMF of the cell is 1.0 V. What is the value of x ? EoAg+,Ag = + 0.8 V. [T = 25oC]
Options
A.2 × 10-2 M
B.2 × 10-3 M
C.1.5 x 10-3 M
D.1.5 × 10-2 M
Solution
H2(Pt) (1 atm) || | Ag+(xM) | Ag
1.0 = (0 + 0.8) -

= pH + log x
log x = - 1.7
= 1.62 × 10-4
x = 2 × 10-2 M
1.0 = (0 + 0.8) -
log x = - 1.7
x = 2 × 10-2 M
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