ElectrochemistryHard

Question

The oxidation number of sulphur in H₂S₂O₇ is :

Options

A.+ 2

B.+ 6

C.+ 4

D.+ 8

Solution

Oxidation number of sulphur in H₂S₂O₇ can be calculated as follows: 2 + 2x - 14 = 0
2x = 14 - 2 = 12
x = = 6

Create a free account to view solution

View Solution Free

Topic: Electrochemistry·Practice all Electrochemistry questions

More Electrochemistry Questions

Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 Ω. The con...A current of 9.65 ampere is passed through the aqueous solution NaCl using suitable electrodes for 1000 s. The amount of...Zn + Cu2+ (aq) ⇋ Cu + Zn2+ (aq) Reaction quotient is Q = . Eocell = 1.10 V. Ecell will be 1.1591 V when :...The first ionisation potential of Na is 5.1 eV. The value of electron gain enthalpy of Na+ will be :-...Standard electrode potentil data are useful for understanding the suitability of an oxidant in a redox titration. Some h...