ElectrochemistryEasy
Question
The oxidation number of sulphur in H2S2O7 is :
Options
A.+ 2
B.+ 6
C.+ 4
D.+ 8
Solution
Oxidation number of sulphur in H2S2O7 can be calculated as follows: 2 + 2x - 14 = 0
2x = 14 - 2 = 12
x =
= 6
2x = 14 - 2 = 12
x =
= 6Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
In an experimental set-up for the measurement of EMF of a half-cell using a reference electrode and a salt bridge, when ...Time required to deposit one millimole of aluminum metal by the passage of 9.65 amperes through aqueous solution of alum...M(s) → Mn+ (aq) + ne-Choose the correct statement(s)....The EMF of the cell: Zn|Zn2+ (0.01 M)||Fe2+ (0.001 M)|Fe at 298 K is 0.2905 V, then the value of equilibrium constant fo...The following galvanic cell: Zn|Zn(NO3)2 (100 ml, 1 M)||Cu(NO3)2 (100 ml, 1 M)|Cu was operated as an electrolytic cell a...