Laws of MotionHard
Question
In figure shown, both block are released from rest. The time to cross each other is
Options
A.2 second
B.3 second
C.1 second
D.4 second
Solution
Acceleration of system
=
g = 
× 10 = 6ms-2
Relative acceleration of block = 12 ms-2
Now 2 + 4 = 1/2 (12) t2 ⇒ t = 1 sec
=
g = × 10 = 6ms-2Relative acceleration of block = 12 ms-2
Now 2 + 4 = 1/2 (12) t2 ⇒ t = 1 sec
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