Laws of MotionHard
Question
In figure shown, both block are released from rest. The time to cross each other is
Options
A.2 second
B.3 second
C.1 second
D.4 second
Solution
Acceleration of system
=
g = 
× 10 = 6ms-2
Relative acceleration of block = 12 ms-2
Now 2 + 4 = 1/2 (12) t2 ⇒ t = 1 sec
=
g = × 10 = 6ms-2Relative acceleration of block = 12 ms-2
Now 2 + 4 = 1/2 (12) t2 ⇒ t = 1 sec
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
Objects A and B each of mass m are connected by light inextensible cord. They are constrained to move on a frictionless ...In the arrangement show in figure, coefficient of friction between the two block is μ = . The force of friction act...Three rigid rods are joined to form an equilateral triangle ABC of side 1m. Three particles carrying charges 20 μ C...The force of friction is due to :-...A body of mass 8 kg is hanging from another body of mass 12 kg. The combination is being pulled by a string with an acce...