Laws of MotionHard
Question
A block tied between two springs is in equilibrium. If upper spring is cut then the acceleration of the block just after cut is 6 m/s2 downwards. Now, if instead of upper spring, lower spring is cut then the magnitude of acceleration of the block just after the cut will be : (Take g = 10 m/s2)
Options
A.16 m/s2
B.4 m/s2
C.cannot be determined
D.none of these
Solution
T1 + T2 = mgIf upper spring is cut
mg − T2 = m × 6 .....(i) If lower spring is cut :
mg − T1 = ma ......(ii)adding (i) and (ii)
2mg − {T1 + T2} = m (a + 6)
2mg − mg = m (a + 6)
mg = m (a + 6)
g = a + 6 a = 4m/s2.
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