Laws of MotionHard
Question
A block tied between two springs is in equilibrium. If upper spring is cut then the acceleration of the block just after cut is 6 m/s2 downwards. Now, if instead of upper spring, lower spring is cut then the magnitude of acceleration of the block just after the cut will be : (Take g = 10 m/s2)
Options
A.16 m/s2
B.4 m/s2
C.cannot be determined
D.none of these
Solution
T1 + T2 = mgIf upper spring is cut
mg − T2 = m × 6 .....(i) If lower spring is cut :
mg − T1 = ma ......(ii)adding (i) and (ii)
2mg − {T1 + T2} = m (a + 6)
2mg − mg = m (a + 6)
mg = m (a + 6)
g = a + 6 a = 4m/s2.
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
In an imaginary atmosphere, the air exerts a small force F on any particle in the direction of the particle′s moti...A person of 72 Kg. Wt. is standing on a weighing machine in a lift. If the lift falls freely, what will be reading of we...A 1 kg particle strikes a wall with velocity 1 m/s at an angle 30o and reflects at the same angle. If its remains in con...Same spring is attached with 2kg, 3kg, and 1kg blocks in three different cases as shown in figure . If X1, X2 , and X3 b...Two weights w1 and w2 are connected by a light thread which passes over a light smooth pulley. If the pulley is raised u...