FrictionHard
Question
Block of mass m is on an inclined plane of angle θ. The coefficient of friction between the block and the plane is μ and tan θ > μ. The block is held stationary by applying a force P parallel to the plane. The direction of force pointing up the plane is taken to be positive. As P is varied from P1 = mg(sinθ - μ cosθ) to P2 = mg (sinθ + μ cosθ), the frictional force f versus P graph will look like


Options
A.

B.

C.

D.

Solution
Initially the frictional force is upwards as P increases frictional force decreases.
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