FrictionHard

Question

Two masses A and B of 10 kg and 5 kg respectively are connected with a string passing over a frictionless pulley fixed at the corner of a table as shown. The coefficient of static friction of A with table is 0.2. The minimum mass of C that may be placed on A to prevent it from moving is

Options

A.15 kg
B.10 kg
C.5 kg
D.12kg

Solution

Apply Newton′s law for system along the string
mB g = m(mA + mC) × g
⇒    mC = − mA = − 10 = 15 kg

Create a free account to view solution

View Solution Free
Topic: Friction·Practice all Friction questions

More Friction Questions

A block of mass M is pulled along a horizontal friction surface by a rope of mass m. If a force P is applied at the free...A block A of mass m1 rests on a horizontal table. A light string connected to it passes over a frictionless pulley at th...A block rests on a rough inclined plane making an angle of 30o with the horizontal. The coefficient of static friction b...In the above question if the external force is applied on 3 kg block, then acceleration of the 3 kg block will be :...When the two surfaces are coated with the lubricant, then they will :...