FrictionMedium
Question
A block of mass 1 kg is stationary with respect to a conveyer belt that is accelerating with 1 m/s2 upwards at an angle of 30o as shown in figure. Which of the following is/are correct?
Options
A.A block of mass 1 kg is stationary with respect to a conveyer belt that is accelerating with 1 m/s2 upwards at an angle of 30o as shown in figure. Which of the following is/are correct?
B.Force of friction on block is 1.5 N upwards.
C.Contact force between the block & belt is 10.5 N.
D.Contact force between the block & belt is 5√3 N.
Solution
(A,C) Block is moving upwards due to friction
fr − mg sin 30 = ma
⇒ fr − 1 × 10 ×
= 1 × 1 ⇒ fr = 6 N
Contact force is the resultant of N and fr
=
=10.5 NCreate a free account to view solution
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