SolutionHard
Question
Depression of freezing point of 0.01 molal aq. CH3COOH solution is 0.02046o. 1 molal urea solution freezes at - 1.86°C. Assuming molality equal to molarity, pH of CH3COOH solution is :
Options
A.2
B.3
C.3.2
D.4.2
Solution
For urea, ᐃTf = kf × m or kf = 
= 1.86
Now for CH3COOH
DTf = i kf m
so i =
= 1.1
Now i = 1 + α
so α = 1.1 - 1 = 0.1
Now CH3COOH ⇋ CH3COO- + H+
C 0 0
C – Cα Cα Cα
[H+] = Cα = 0.01 × 0.1 = 0.001
so pH = 3.
= 1.86Now for CH3COOH
DTf = i kf m
so i =
= 1.1Now i = 1 + α
so α = 1.1 - 1 = 0.1
Now CH3COOH ⇋ CH3COO- + H+
C 0 0
C – Cα Cα Cα
[H+] = Cα = 0.01 × 0.1 = 0.001
so pH = 3.
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