SolutionHard
Question
On mixing 3g of non-volatile solute in 200 mL of water, its Boiling point (100oC) be comes 100.52oC. If Kb for water is 0.6 K/n then molecular wt. of solute is :
Options
A.10.5 mol-1
B.12.6 mol-1
C.15.7 mol-1
D.17.3 mol-1
Solution
ᐃT = Kb 
0.52 = 0.6 ×
m =
= 17.3g mole-1
0.52 = 0.6 ×
m =
= 17.3g mole-1Create a free account to view solution
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