SolutionHard
Question
Water and chlorobenzene are immiscible liquids. Their mixture boils at 90oC under a reduced pressure of 7.82 × 104 Pa. The vapour pressure of pure water at 90oC is 7.03 × 104 Pa. On weight percent basis, chlorobenzene in the distillate is equal to (mol. wt. of chlorobenzene is 112.5 g mol-1)
Options
A.50
B.60
C.70
D.80
Solution
PV = nRT
Pmix = 7.82 × 104 Pa
P2 + P1 = 7.82 × 104 Pa
P1 = 7.03 × 104 Pa
∴ P2 = 0.79 × 104 Pa
P ∞ n
∴
w2 = w1
= 0.70
Pmix = 7.82 × 104 Pa
P2 + P1 = 7.82 × 104 Pa
P1 = 7.03 × 104 Pa
∴ P2 = 0.79 × 104 Pa
P ∞ n
∴
w2 = w1
= 0.70Create a free account to view solution
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