SolutionHard
Question
If pKa = - log Ka = 4, and Ka = Cx2 then Van′t Hoff factor for weak monobasic acid when C = 0.01 M is :
Options
A.1.01
B.1.02
C.1.10
D.1.20
Solution
HA ⇋ H+ + A-
i = [1 + (y - 1) x] = 1 + x
pKa = 4 = - log Ka
∴ Ka = 10-4 = Cx2
1 × 10-4 = 0.01 × x2 ⇒ x = 0.1 ∴ i = 1 + x = 1.1
i = [1 + (y - 1) x] = 1 + x
pKa = 4 = - log Ka
∴ Ka = 10-4 = Cx2
1 × 10-4 = 0.01 × x2 ⇒ x = 0.1 ∴ i = 1 + x = 1.1
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