Current Electricity and Electrical InstrumentHard
Question
n identical cells are joined in series with its two cells A and B in the loop with reversed polarities. EMF of each cell is E and internal resistance r. Potential difference across cell A or B is (here n > 4)
Options
A.
B.2E
C.
D.2E 
Solution
If all were in series all of them would have being getting discharged. But since, 2 are in opposite polarity, they will be getting charged.
V = E + iR getting charged i =
as (nE - 4) as 4 batteries will be cancelled out
= E +
R, = E + 
V = E + iR getting charged i =
as (nE - 4) as 4 batteries will be cancelled out
= E +
Create a free account to view solution
View Solution FreeTopic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions
More Current Electricity and Electrical Instrument Questions
A 1Ω voltmeter has range 1V. Find the additional resistance which has to join in series in voltmeter to increase th...Which of the following is the wrong statement?...In the ladder network shown, current through the resistor 3 Ω is 0.25 A. The input voltage ′V′ is equal...In the following circuit, the potential difference between the points A and B will be (VA - VB) :...A diode detector is used to detect an amplitude modulated wave of 60% modulation by using a condenser of capacity 250 pi...