Atomic StructureHard
Question
If the value of En = - 78.4 kcal/mole, the order of the orbit in hydrogen atom is :
Options
A.4
B.3
C.2
D.1
Solution
En = - 78.4 kcal/mole = - 78.4 × 4.2 = - 329.28 kJ/mole
= -
eV = - 3.4 eV. (energy of II orbit of H atom).
= -
eV = - 3.4 eV. (energy of II orbit of H atom). Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
The amount of energy released when an electron jumps from the seventh excited state to the first excited state in He+ io...What possibly can be the ratio of the de Broglie wavelengths for two electrons each having zero initial energy and accel...The K and L shell of an element are completely filled and there are 16 electrons in M-shell and 2 electrons in N-shell. ...The possible value of l and m for the last electron in the Cl- ion are :...No. of visible lines when an electron returns from 5th orbit to ground state in H-spectrum :-...