Atomic StructureHard
Question
If the value of En = - 78.4 kcal/mole, the order of the orbit in hydrogen atom is :
Options
A.4
B.3
C.2
D.1
Solution
En = - 78.4 kcal/mole = - 78.4 × 4.2 = - 329.28 kJ/mole
= -
eV = - 3.4 eV. (energy of II orbit of H atom).
= -
eV = - 3.4 eV. (energy of II orbit of H atom). Create a free account to view solution
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