Momentum and CollisionHard
Question
A particle of mass = 0.1 kg is released from a point A of a wedge of mass M = 2.4 kg free to slide friction less horizontal the smooth face AB of the wedge. When the velocity of the wedge is plane is 0.2 m/s the velocity of the particle in m/s relative to the wedge is
Options
A.4.8
B.5
C.7.5
D.10
Solution
COME : - MV + m(vcos 60 - V) = 0 ⇒ v = 10 m/s
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