Atomic StructureHard
Question
A certain dye absorbs light of l = 4000 
and then fluorescence light of 5000 
. Assuming that under given conditions 50% of the absorbed energy is re-emitted out as fluorescence, calculate the ratio of number of quanta emitted out to the number of quanta absorbed.
and then fluorescence light of 5000 . Assuming that under given conditions 50% of the absorbed energy is re-emitted out as fluorescence, calculate the ratio of number of quanta emitted out to the number of quanta absorbed.Options
A.5/8
B.8/5
C.3/8
D.8/3
Solution
Eemitted = 
× No. of absorbed photon × Energy of absorbed photon.
∴ ne ×
∴
.
× No. of absorbed photon × Energy of absorbed photon.∴ ne ×
∴
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