Momentum and CollisionHard
Question
Three interacting particles of masses 100g, 200g, and 400g each have a velocity of 20m/s magnitude along the positive direction of x – axis y-axis and z-axis. Due to force interaction third particle stops moving. The velocity of the second particle is (10ĵ + 5
), What is the velocity of the particle ?
), What is the velocity of the particle ? Options
A.20î + 20ĵ + 70
B.10î + 20ĵ + 8
C.30î + 10ĵ + 7
D.15î + 5ĵ + 60
Solution
Initial momentum = m1
+ m2
+ m3
= 2î + 4ĵ + 8
When the third particle stop the final momentum = m1 + m2 + m3 = 0.1
+ 0.2(10ĵ + 5
) + 
By principle of conservation momentum 0.1
+ 2ĵ + 
= 2î + 4ĵ + 8
; = 20î + 20ĵ + 70
+ m2 + m3 = 2î + 4ĵ + 8When the third particle stop the final momentum = m1
+ m2 + m3 = 0.1 + 0.2(10ĵ + 5) + By principle of conservation momentum 0.1
+ 2ĵ + = 2î + 4ĵ + 8 ; = 20î + 20ĵ + 70Create a free account to view solution
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