Laws of MotionMedium
Question
A machine gun fires a bullet of mass 40 g with a velocity 1200 ms-1. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most?
Options
A.one
B.four
C.two
D.three
Solution
Change in momentum for each bullet fired is
× 1200 = 48 N
If a bullet fired exerts a force of 48 N on man′s hand so ρ man can exert maximum force of 144 N, number of bullets that can be fired = 144/48 = 3 bullets.
× 1200 = 48 NIf a bullet fired exerts a force of 48 N on man′s hand so ρ man can exert maximum force of 144 N, number of bullets that can be fired = 144/48 = 3 bullets.
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