Atomic StructureHard
Question
Photon having wavelength 310 nm is used to break the bond of A2 molecule having bond energy
288 kJ mol-1 then % of energy of photon converted to the K.E. is [hc = 12400 ev
, 1 ev = 96 kJ/mol]
288 kJ mol-1 then % of energy of photon converted to the K.E. is [hc = 12400 ev
, 1 ev = 96 kJ/mol]Options
A.25
B.50
C.75
D.80
Solution
Energy of one photon = 
= 4ev = 4 × 96 = 384 kJ mol-1
∴ % of energy converted to K.E. =
× 100 = 25%
= 4ev = 4 × 96 = 384 kJ mol-1∴ % of energy converted to K.E. =
× 100 = 25% Create a free account to view solution
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