Solid StateHard
Question
In a compound, oxide ions are arranged in cubic close packing arrangement. Cations A occupy one-sixth of the tetrahedral voids and cations B occupy one-third of the octahedral voids. The formula of the compound is
Options
A.A2BO3
B.AB2O3
C.A2B2O2
D.ABO3
Solution
no. of oxide ions = 4
no. of A particles =
× 8 = 
no. of B particles =
× 4 = 
so formula is A4/3 B4/3O4 or ABO3
no. of A particles =
× 8 = no. of B particles =
× 4 = so formula is A4/3 B4/3O4 or ABO3
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