Solid StateHard
Question
An ionic crystalline solid MX3 has a cubic unit cell. Which of the following arrangement of the ions is consistent with the stoichiometry of the compound?
Options
A.M3+ ions at the corners and X− ions at the face centres.
B.M3+ ions at the corners and X− ions at the body centres.
C.X− ions at the corners and M3+ ions at the face centres.
D.X− ions at the corners and M3+ ions at the body centres.
Solution
$Z_{M^{3 +}} = 8 \times \frac{1}{8} = 1\left( \text{If }\text{M}^{3 +}\text{are at corners} \right);Z_{X^{-}} = 6 \times \frac{1}{2} = 3\left( \text{If }F^{-}\text{are at face centres} \right);$
Create a free account to view solution
View Solution FreeMore Solid State Questions
In a cubic closest packed structure of mixed oxides, the lattice is made up of oxide ions. Tetrahedral voids are occupie...Lithium crystallizes in a body centered cubic lattice. How many next–nearest neighbors does each Li have?...The number of octahedral voids per unit BCC cell is...Square packed sheets are arranged on the top of other such that a sphere in the next layer rests on the center of a squa...In a face centerd lattice of X and Y, X atoms are present at the corners while Y atoms are at face centers. Then the for...