Solid StateHard
Question
An ionic crystalline solid MX3 has a cubic unit cell. Which of the following arrangement of the ions is consistent with the stoichiometry of the compound?
Options
A.M3+ ions at the corners and X− ions at the face centres.
B.M3+ ions at the corners and X− ions at the body centres.
C.X− ions at the corners and M3+ ions at the face centres.
D.X− ions at the corners and M3+ ions at the body centres.
Solution
$Z_{M^{3 +}} = 8 \times \frac{1}{8} = 1\left( \text{If }\text{M}^{3 +}\text{are at corners} \right);Z_{X^{-}} = 6 \times \frac{1}{2} = 3\left( \text{If }F^{-}\text{are at face centres} \right);$
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