Atomic StructureHard
Question
n-Butane (C4H10) is produced by monobromination of C2H6 followed by Wurtz reaction. Calculate the volume of ethane at STP required to produce 55 g of n-butane. The bromination takes place with 90% yield and the Wurtz reaction with 85% yield.
Options
A.27.75 L
B.55.5 L
C.55.5 L
D.5.55 L
Solution
2C2H6 + Br2 → 2C2H5Br + HBr
12 × 4 + 10 = 58 g
58 g of n-butane ⇒ 2 × 22.4 L of C2H6 at STP
⇒ 2 × 22.4 ×
58 g of n-butane = 58.56 L
58 g of n-butane = 55.5 L
12 × 4 + 10 = 58 g
58 g of n-butane ⇒ 2 × 22.4 L of C2H6 at STP
⇒ 2 × 22.4 ×
58 g of n-butane = 58.56 L
58 g of n-butane = 55.5 L
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