Photoelectric EffectMedium
Question
In photoelectric effect, stopping depends on
Options
A.Frequency of the incident light
B.intensity of the of the incident light by varies source distance
C.emitter′s properties
D.frequency and intensity of the light
Solution
hv = hv0 + + eVs ; Vs =
hv = hv0 + eVs ; Vs =
; eVs = hv - 
Here v = frequency of incident of light and
= properties of emitter
hv = hv0 + eVs ; Vs =
Here v = frequency of incident of light and
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