Nuclear Physics and RadioactivityHard

Question

In photoelectric effect, stopping depends on

Options

A.Frequency of the incident light

B.intensity of the of the incident light by varies source distance

C.emitter′s properties

D.frequency and intensity of the light

Solution

hv = hv₀ + + eV_s ; V_s =
hv = hv₀ + eV_s ; V_s =

; eV_s = hv -
Here v = frequency of incident of light and
= properties of emitter

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