Photoelectric EffectMedium
Question
Two particles have charges. If they are accelerated through identical potential differences, then the ratio of their de Broglie wavelength would be
Options
A.λ1 : λ2 = 1 : 1
B.λ1 : λ2 = m1 : m2
C.λ1 : λ2 = √m1 : √m2
D.λ1 : λ2 = √m2 : √m1
Solution
K.E. = qᐃV
λ1 =
; λ2 = 
∵ q = q1 = q2 & ᐃV is same ∴
λ1 =
; λ2 = ∵ q = q1 = q2 & ᐃV is same ∴
Create a free account to view solution
View Solution FreeMore Photoelectric Effect Questions
As the intensity of the given source increases :-...An electron with initial kinetic energy of 100 eV is accelerated through a potential difference of 50 V. Now the de - Br...The mass of nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of nu...Photo electron emitted from the surface of sodium metal are :-...Protons and singly ionized atoms of U235 & U238 are passed in turn (which means one after the other and not at the same ...