Nuclear Physics and RadioactivityHard
Question
Two particles have charges. If they are accelerated through identical potential differences, then the ratio of their de Broglie wavelength would be
Options
A.λ1 : λ2 = 1 : 1
B.λ1 : λ2 = m1 : m2
C.λ1 : λ2 = √m1 : √m2
D.λ1 : λ2 = √m2 : √m1
Solution
K.E. = qᐃV
λ1 =
; λ2 = 
∵ q = q1 = q2 & ᐃV is same ∴
λ1 =
; λ2 = ∵ q = q1 = q2 & ᐃV is same ∴
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