Nuclear Physics and RadioactivityHard

Question

An electron with initial kinetic energy of 100 eV is accelerated through a potential difference of 50 V. Now the de - Broglie wavelength of electron becomes

Options

A.1
B.
C.√3
D.12.27

Solution

For electron   λdb = = 1

Create a free account to view solution

View Solution Free
Topic: Nuclear Physics and Radioactivity·Practice all Nuclear Physics and Radioactivity questions

More Nuclear Physics and Radioactivity Questions