Nuclear Physics and RadioactivityHard
Question
The half life of a radioactive element is 10 days. If the mass of the specimen reduces to 1/10th then the time taken is :-
Options
A.100 days
B.50 days
C.33 days
D.16 days
Solution
N = N0e-λt⇒ 
= N0e-λt⇒ ln (10) = - λt
⇒ t =
T1/2 ⇒ t = 33 days
= N0e-λt⇒ ln (10) = - λt⇒ t =
T1/2 ⇒ t = 33 daysCreate a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
A nuclear fusion reaction is given below : 1H2 + 1H2 → 2He3 + n + 3.2 MeVHow much energy will be generated when 2 ...The electron in hydrogen atom a sample is in nth excited state, then the number of different spectrum lines obtained in ...The de Broglie wave are associated with moving particles. These particle may be -...The activity of radio active sample is measured as N0 counts per minute at t = 0 and N0 /e counts per minute at t = 5 mi...A neutron collides head - on with a stationary hydrogen atom in ground state. Which of the following statements are corr...