Nuclear Physics and RadioactivityHard
Question
The half life of a radioactive element is 10 days. If the mass of the specimen reduces to 1/10th then the time taken is :-
Options
A.100 days
B.50 days
C.33 days
D.16 days
Solution
N = N0e-λt⇒ 
= N0e-λt⇒ ln (10) = - λt
⇒ t =
T1/2 ⇒ t = 33 days
= N0e-λt⇒ ln (10) = - λt⇒ t =
T1/2 ⇒ t = 33 daysCreate a free account to view solution
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