Nuclear Physics and RadioactivityHard
Question
Per nucleon energy of 3Li7 and 2He4 nucleus is 5.60 meV and 7.06 MeV, than in
3Li7 + 1P1 → 22He4 energy release is : -
3Li7 + 1P1 → 22He4 energy release is : -
Options
A.29.6 MeV
B.2.4 MeV
C.8.4 MeV
D.17.3 MeV
Solution
Q = - 7(5.6) + [4(7.06)]2 ⇒ Q = 17.3 MeV
Create a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
Energy liberated in nuclear reaction is...Starting with a sample of pure 66Cu, 7/8 of it decays into Zn in 15 minutes. The corresponding half-life is...Half life of a radioactive material is 4 days. The amount of the substance will remain after 16 days,.....(initial activ...A vessel of 831cc contains at 0.6 atm and 27oC. If half life of is 12.3 years then the activity of the gas is -...Outside the nucelus :...