Nuclear Physics and RadioactivityHard
Question
The stopping potential for photo electron emitted from a metal surface of work function 1.7 eV is 10.4V. Select correct choice
Options
A.The wavelength of light used is 1022 
B.The wavelength of light used is 970
C.The light used is emitted by hydrogen gas sample which de-excites from n = 3 to n = 1
D.The light used is emitted by hydrogen gas sample which de-excites from n = 4 to n = 1
Solution
Kmax 10.4eV ; 
= 1.7 eV
E = 10.4 + 1.7 = 12.1 eV ⇒ n = 3 to n = 1
12.1 =
= 1.7 eVE = 10.4 + 1.7 = 12.1 eV ⇒ n = 3 to n = 1
12.1 =
Create a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
Half-life of a radioactive substance is 20 minutes. Difference between points of time when it is 33% disintegrated and 6...90Th232 an isotope of thorium decays in ten stages emitting six α-particles and four β-particles in all. The e...Two radioactive martial A1 and A2 have decay constants of 10λ0 and λ0. If initially they have same number of n...For a doubly ionised Li-atom...A photoelecrtic cell illuminated by a point source of light 1 m away. When the source is Shifted to 2m then-...