ParabolaMedium
Question
The triangle PQR of area ′A′ is inscribed in the parabola y2 = 4ax such that vertex P lies at the vertex of the parabola and the base QR is a focal chord. The modulus of the difference of the ordinates of the points Q and R is -
Options
A.A/2a
B.A/a
C.2A/a
D.4a/a
Solution
Since QR is focal chord so vertex of Q is (at12, 2at1)
and R is (at22, 2at2)
area of ᐃPQR =
A =
|2a2t12 t2 - 2a2t1t22|
A =
| 2at1 - 2at2 | [t1t2 = - 1]
and R is (at22, 2at2)
area of ᐃPQR =
A =
|2a2t12 t2 - 2a2t1t22|A =
| 2at1 - 2at2 | [t1t2 = - 1]Create a free account to view solution
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