ParabolaMedium
Question
The angle between normal chords of a parabola which subtend right angle at the vertex is tan-1 k, then k is
Options
A.√2
B.2
C.2√2
D.4
Solution
t2 = - t1 -
, also t1t22 = - 4
⇒ - 4 = - t12 - 2 ⇒ t12 = 2 ⇒ t1 = ± √2
Slope of normal chord become
m1 = √2, m2 = - √2
tan θ = | - 2√2| ⇒ θ = tan-1|2√2|
, also t1t22 = - 4⇒ - 4 = - t12 - 2 ⇒ t12 = 2 ⇒ t1 = ± √2
Slope of normal chord become
m1 = √2, m2 = - √2
tan θ = | - 2√2| ⇒ θ = tan-1|2√2|
Create a free account to view solution
View Solution FreeMore Parabola Questions
The equation of the circle drawn with the focus of the parabola (x - 1)2 - 8y = 0 as its centre and touching the parabol...A parabola $y = ax^{2} + bx + c$ crosses the $x$-axis at $(\alpha,0)(\beta,0)$ both to the right of the origin. A circle...The tangent PT and the normal PN to the parabola y2 = 4ax at a point P on it meet its axis at points T and N, respective...Let (x, y) be any point on the parabola y2 = 4x. Let P be the point that divides the line segment from (0, 0) to (x, y) ...The area of the region bounded by the parabola (y - 2)2 = x - 1, the tangent to the parabola at the point (2, 3) and the...