ParabolaHard
Question
The angle between normal chords of a parabola which subtend right angle at the vertex is tan-1 k, then k is
Options
A.√2
B.2
C.2√2
D.4
Solution
t2 = - t1 -
, also t1t22 = - 4
⇒ - 4 = - t12 - 2 ⇒ t12 = 2 ⇒ t1 = ± √2
Slope of normal chord become
m1 = √2, m2 = - √2
tan θ = | - 2√2| ⇒ θ = tan-1|2√2|
, also t1t22 = - 4⇒ - 4 = - t12 - 2 ⇒ t12 = 2 ⇒ t1 = ± √2
Slope of normal chord become
m1 = √2, m2 = - √2
tan θ = | - 2√2| ⇒ θ = tan-1|2√2|
Create a free account to view solution
View Solution FreeMore Parabola Questions
The length of the chord of the parabola y2 = x which is bisected at the point (2, 1) is -...The triangle PQR of area ′A′ is inscribed in the parabola y2 = 4ax such that vertex P lies at the vertex of ...The area of the region bounded by the parabola (y - 2)2 = x - 1, the tangent to the parabola at the point (2, 3) and the...If two tangents drawn from a point P to the parabola y2 = 4x are at right angles, then the locus of P is...Locus of the intersection of the tangents at the ends of the normal chords of the parabola y2 = 4ax is -...