ParabolaHard

Question

F1 and F2 are focus of hyperbola 16x2 - 9y2 - 32x = 128.
S = 0 is equation of parabola whose vertex is F1 and focus is F2, then

Options

A.S can be y2 - 40x - 160 = 0
B.S can be y2 + 40x + 200 = 0
C.S can be y2 - 40x + 200 = 0
D.S can be y2 + 40x - 240 = 0

Solution

= 1
ae = 5 & centre (1, 0) foci are (- 4, 0) & (6, 0)
parabola whose vertex is (-4, 0) & focus (6, 0) is y2 = 40(x + 4)
parabola whose vertex is (6, 0) & focus (-4, 0) is y2 = -40(x - 6)

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