Hard
Question
The horizontal range of a projectile is R and the maximum height attained by it is H. A strong wind now begins to blow in the direction of motion of the projectile, giving constant horizontal acceleration = g/2. Under the same conditions of projection. Find the horizontal range of the projectile.
Options
A.R + H
B.R + 2H
C.R
D.R + H/2
Solution
New horizontal range
= R +
× T2 = R + 
= R + 2H (∵ H =
)
= R +
× T2 = R + = R + 2H (∵ H =
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