KinematicsHard
Question
A projectile is given an initial velocity of 
m/s, where 
is along the ground and 
is along the vertical. If g = 10 m/s2, the equation of its trajectory is :
m/s, where is along the ground and is along the vertical. If g = 10 m/s2, the equation of its trajectory is :Options
A.y = x - 5x2
B.y = 2x - 5x2
C.4y = 2x - 5x2
D.4y = 2x - 25x2
Solution
u = √5 and tan θ = 2
so by y
⇒
⇒ y = 2x - 5x2
so by y
⇒
⇒ y = 2x - 5x2
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