KinematicsHard
Question
A particle leaves the origin an initial velocity 
= 3
m/s and a constant acceleration 
= (-1.0î - 0.5ĵ) m/s2 Its velocity 
and position vector 
when it reaches its maximum x-co-ordinate are :-
= 3 m/s and a constant acceleration = (-1.0î - 0.5ĵ) m/s2 Its velocity and position vector when it reaches its maximum x-co-ordinate are :- Options
A. = - 2ĵ
= - 2ĵB. = - 1.5ĵ m/s
= - 1.5ĵ m/sC.
= - (4.5î - 2.25ĵ) m
= - (4.5î - 2.25ĵ) mD. = - (3î - 2ĵ) m
= - (3î - 2ĵ) mSolution
(t) = (3 - 1 × t) î + (0 - 0.5) ĵ ..............(i)For maximum positive x coordinate when vx becomes zero
∴ 3 - t = 0 ⇒ t = 3 sec
then
(3) = 4.5 î - 2.25 ĵCreate a free account to view solution
View Solution FreeMore Kinematics Questions
A projectile is projected angle (α > 45o) with an initial velocity u. The time t, which its magnitude of horizon...The position of a particle moving along x-axis depends on time as x = 2(1 - e-3t). Choose the INCORRECT statement....A projectile is thrown into space so as to have the maximum possible horizontal range equal to 100m. Taking the point of...A particle moves in straight line in same direction for 20 seconds with velocity 3 m/s and then moves with velocity 4 m ...The dimensions of the quantities in one (or more) of the following pairs are the same. Identify the pair (s)...