KinematicsMedium
Question
A particle leaves the origin an initial velocity
= 3
m/s and a constant acceleration
= (-1.0î - 0.5ĵ) m/s2 Its velocity
and position vector
when it reaches its maximum x-co-ordinate are :-
Options
A.
= - 2ĵ
B.
= - 1.5ĵ m/s
C.
= - (4.5î - 2.25ĵ) m
D.
= - (3î - 2ĵ) m
Solution
For maximum positive x coordinate when vx becomes zero
∴ 3 - t = 0 ⇒ t = 3 sec
then
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