KinematicsHard
Question
The figure shows the v - t graph of a particle moving in straight line Find the time particle returns to the starting point.
Options
A.30 sec
B.34.5 sec
C.36.2 sec
D.35.4 sec
Solution
For returning, the starting point
Area of (ᐃOAB) = Area of (ᐃBCD)
× 20 × 25 = 
× t × 4t ⇒ t = 5
11.2
∴ Required time = 25 + 11.2 = 36.2
Area of (ᐃOAB) = Area of (ᐃBCD)
× 20 × 25 = × t × 4t ⇒ t = 5 11.2∴ Required time = 25 + 11.2 = 36.2
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