A projectile is thrown upward at an angle $60^{\circ}$ with the horizontal. The speed of the project

Question

A projectile is thrown upward at an angle $60^{\circ}$ with the horizontal. The speed of the projectile is $20	ext{ }m/s$ when its direction of motion is $45^{\circ}$ with the horizontal. The initial speed of the projectile is $\_\_\_\_$ $m/s$.

Accepted Answer

$${ucos60^{\circ} = \frac{20}{\sqrt{2}} }{\frac{u}{2} = \frac{20}{\sqrt{2}} }{u = \frac{40}{\sqrt{2}} }{u = 20\sqrt{2}	ext{ }m/s}$$

Question

Options

Solution

More Kinematics Questions