KinematicsMedium
Question
A projectile is thrown upward at an angle $60^{\circ}$ with the horizontal. The speed of the projectile is $20\text{ }m/s$ when its direction of motion is $45^{\circ}$ with the horizontal. The initial speed of the projectile is $\_\_\_\_$ $m/s$.
Options
A.$40\sqrt{2}$
B.40
C.$20\sqrt{3}$
D.$20\sqrt{2}$
Solution
$${ucos60^{\circ} = \frac{20}{\sqrt{2}} }{\frac{u}{2} = \frac{20}{\sqrt{2}} }{u = \frac{40}{\sqrt{2}} }{u = 20\sqrt{2}\text{ }m/s}$$
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