KinematicsHard
Question
A particle P is projected from a point on the surface of smooth inclined plane (see figure). Simultaneously another particle Q released on the smooth inclined plane from the same position P and Q collide after t = 4 second The speed of projection of P is : -
Options
A.5 m/s
B.10 m/s
C.15 m/s
D.20 m/s
Solution
Time of light =
........(i)
(angle of projection = θ)
Distance traveled by Q on
incline in 4 secs in 4 sec is
= 0 +
× 
× 42 = 40√3
& the angle of particle ‘P’ is 40√3
= u cos θ × 4 + × 42 = 40 √3
= u cos θ = 0 ; so θ = 90o
from equation (i) u = 10 m/s
........(i)(angle of projection = θ)
Distance traveled by Q on
incline in 4 secs in 4 sec is
= 0 +
× × 42 = 40√3& the angle of particle ‘P’ is 40√3
= u cos θ × 4 +
× 42 = 40 √3= u cos θ = 0 ; so θ = 90o
from equation (i) u = 10 m/s
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