KinematicsHard
Question
From a motorboat moving downstream with a velocity 2 m/s respectest to river, a stone is thrown. The ston falls on an ordinary boat at the instant when the motorboat collides with the velocity of the ordinary boat respect to river is zero. The river flow velocity is given to be is given to be 1 m/s The initial velocity vector of the stone with respect to earth is : -
Take the value of g = 10 m/s2
Initial separation between the two boats is 20 m.
Take the value of g = 10 m/s2
Initial separation between the two boats is 20 m.
Options
A.2i + 20j
B.3i + 40 j
C.3i + 50j
D.2i + 50j
Solution
Time of collision of two boat = 20/2 = 10 sec. As given in question i.e. the time of flight of stone is also equal to 10 sec. so vertical component of stone initially is 50 m/s and the horizontal component w.r.t motorboat equals to 2 m/s.
Hence
= 3î + 50ĵ
Hence
= 3î + 50ĵ Create a free account to view solution
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