Hard
Question
A ball is dropped vertically from a height d above the ground. It hits the ground and bounces up vertically to a height d/2. Neglecting subsequent motion and air resistance, its velocity v varies height h above the ground as
Options
A.
B.
C.
D.
Solution
(a) For uniformaly accelerated/decelerated motion
v2 = u2
2ghi.e., v-h graph will be a parabola (motion equation is quadratic)
(b) Initially velocity is downwards (-ve) and then after collision it reverses its its direction with lesser magnitude, i.e. velocity is upwards (+ve). Graph (a) satisfies both these conditions.
Therefore, corect answer is (a)
Now that time t = 0 corresponds to the point on the graph where h = d
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