KinematicsHard
Question
A particle moves along a straight line OX. At a time t (in seconds) The distance x (in meters) of the particle from O is given by x = 40 + 12 t - t3. How long would the particle travel before coming to rest ?
Options
A.24 m
B.40 m
C.56 m
D.16 m
Solution
x = 40 + 12t - t3.
Speed
= 0 + 12 - 3t2 ⇒ t = ± 2 sec
∴ x(2) = 40 + 12 × 2 - 23
= 64 - 8 = 56 m.
at t = 0, x(0) = 40
ᐃx = x(2) - x(0) = 16
Speed
= 0 + 12 - 3t2 ⇒ t = ± 2 sec∴ x(2) = 40 + 12 × 2 - 23
= 64 - 8 = 56 m.
at t = 0, x(0) = 40
ᐃx = x(2) - x(0) = 16
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