KinematicsHard
Question
An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by : 
= - 2.5 √v where v is the instantaneous speed. The time taken by the object, to come to rest, would be :
= - 2.5 √v where v is the instantaneous speed. The time taken by the object, to come to rest, would be :Options
A.2 s
B.4 s
C.8 s
D.1 s
Solution
= - 2.5 √vIntegrating the above equation.
⇒ 2√v = - 2.5 t + C
at t = 0, v = 6.25 ⇒ C = 5
at v = 0, ⇒ t =
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