KinematicsHard
Question
In the figure shown the acceleration of A is 
= 15î + 15ĵ then the acceleration of B is (A remains in contact)In the figure shown the acceleration of A is = 15î + 15ĵ then the acceleration of B is (A remains in contact) with B
= 15î + 15ĵ then the acceleration of B is (A remains in contact)In the figure shown the acceleration of A is = 15î + 15ĵ then the acceleration of B is (A remains in contact) with B
Options
A.6î
B.-15î
C.-10î
D.-5î
Solution
Let acceleration of B 
= aBî
Then acceleration of A w.r.t
B =
= (15 - aB) î + 15 ĵ
This acceleration must be along the inclined plane
so tan 37o =
aB = - 5
⇒= - 5î
= aBîThen acceleration of A w.r.t
B =
= (15 - aB) î + 15 ĵThis acceleration must be along the inclined plane
so tan 37o =
aB = - 5⇒
= - 5îCreate a free account to view solution
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