KinematicsHard
Question
The relation time t and distance x is t = αx2 + βx where α and β are constants. The retardation is : -
Options
A.2αv3
B.2βv2
C.2αβv2
D.2β2v2
Solution
t = αx2 + βx ⇒ 1 = (2α x + β) v ⇒ v = 
∴ Acceleration =
v = 2αv2
∴ Acceleration =
v = 2αv2Create a free account to view solution
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